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Ex 11.3, 7 - 36x2 + 4y2 = 144 Find foci, vertices, latus - Ex 11.3

Ex 11.3,  7 - Chapter 11 Class 11 Conic Sections - Part 2
Ex 11.3,  7 - Chapter 11 Class 11 Conic Sections - Part 3


Transcript

Ex 11.3, 7 Find the coordinates of the foci, the vertices, the length of major axis, the minor axis, the eccentricity and the length of the latus rectum of the ellipse 36x2 + 4y2 = 144 Given 36x2 + 4y2 = 144. Dividing equation by 144 36 2 144 + 4 2 144 = 1 1 4 x2 + 1 36 y2 = 1 Since 4 < 36 Above equation is of form 2 2 + 2 2 = 1 Comparing (1) and (2) We know that c2 = a2 b2 c2 = 32 c = 32 c = 4 Coordinate of foci = (0, c) = (0, 4 2 ) So coordinates of foci are (0, 4 2 ), (0, 4 2 ) Vertices = (0, a) = (0, 6) Thus, vertices are (0, 6) & (0, 6) Length of major axis = 2a = 2 6 = 12 Length of minor axis = 2b = 2 2 = 4 Eccentricity e = = 4 2 6 = 2 2 3 Length of latus rectum = 2 2 = 2 4 6 = 4 3

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.