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Ex 10.3, 12 - Chapter 10 Class 11 Conic Sections
Last updated at May 29, 2023 by Teachoo
Ex 10.3
Ex 10.3, 1
Ex 10.3, 2 Important
Ex 10.3, 3
Ex 10.3, 4
Ex 10.3, 5 Important
Ex 10.3, 6
Ex 10.3, 7 Important
Ex 10.3, 8
Ex 10.3, 9
Ex 10.3, 10
Ex 10.3, 11 Important
Ex 10.3, 12 Important You are here
Ex 10.3, 13
Ex 10.3, 14 Important
Ex 10.3, 15
Ex 10.3, 16 Important
Ex 10.3, 17
Ex 10.3, 18 Important
Ex 10.3, 19 Important
Ex 10.3, 20
Chapter 10 Class 11 Conic Sections
Serial order wise
- Ex 10.1
- Ex 10.2
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Ex 10.3
- Ex 10.4
- Examples
- Miscellaneous
Transcript
Ex 10.3, 12 Find the equation for the ellipse that satisfies the given conditions: Vertices (±6, 0), foci (±4, 0) Given Vertices (± 6, 0) The vertices are of the form (±a, 0) Hence, the major axis is along x-axis & Equation of ellipse is of the form 𝒙^𝟐/𝒂^𝟐 + 𝒚^𝟐/𝒃^𝟐 = 1 From (1) & (2) a = 6 Also given coordinate of foci = (±4, 0) We know that foci = (± c, 0) So c = 4 We know that c2 = a2 − b2 (4) 2 = (6) 2 − b2 b2 = (6) 2 − (4) 2 b2 = 36 − 16 b2 = 20 Equation of ellipse is 𝑥^2/𝑎^2 + 𝑦^2/𝑏^2 = 1 Putting values 𝒙^𝟐/𝟑𝟔 + 𝒚^𝟐/𝟐𝟎 = 1
