Question 38 (iii) (Choice B) - CBSE Class 10 Sample Paper for 2026 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards

Last updated at August 26, 2025 by Teachoo

[SQP] If Shreya moves to a point which is at a distance of 41/√3 from - CBSE Class 10 Sample Paper for 2026 Boards - Maths Standard

part 2 - Question 38 (iii) (Choice B) - CBSE Class 10 Sample Paper for 2026 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards - Class 10

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Transcript

Question 38 (iii) - Choice (B) If Shreya moves to a point which is at a distance of 41/√3 m from the India Gate, then find the angle of elevation made by her eye to the top of India Gate.Now, Shreya is standing at a distance of 41/√3 m away So, YB = XC = 𝟒𝟏/√𝟑 m In right angle triangle AXC, tan X = (𝑆𝑖𝑑𝑒 𝑜𝑝𝑝𝑜𝑠𝑖𝑡𝑒 𝑡𝑜 𝑎𝑛𝑔𝑙𝑒" " 𝑋)/(𝑆𝑖𝑑𝑒 𝑎𝑑𝑗𝑎𝑐𝑒𝑛𝑡 𝑡𝑜 𝑎𝑛𝑔𝑙𝑒" " 𝑋) tan X = AC/XC tan X = 41/(41/√3) tan X = 41 ×√3/41 tan X = √3 Thus, ∠ X = 60° So, required angle of elevation is 60°

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo

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