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Question 38 (Case Based Questions) India gate (formerly known as All India war memorial) is located near Karthavya path. (formerly Rajpath) at New Delhi. It stands as a memorial to 74187 soldiers of Indian Army, who gave their life in the first world war. This 42m tall structure was designed by Sir Edwin Lutyens in the style of Roman triumphal arches. A student Shreya of height 1 m visited India Gate as a part of her study tour. Question 38 (i) What is the angle of elevation from Shreya’s eye to the top of India Gate, if she is standing at a distance of 41m away from the India Gate?Shreya is 1 m tall So, PQ = 1 m India gate is 42m tall, So, AB = 30 m Now, AC = AB – BC Since PQ = BC India gate is 42m tall, So, AB = 30 m Now, AC = AB – BC Since PQ = BC AC = AB – PQ AC = 42 – 1 AC = 41 m Also, Shreya is standing at a distance of 41m away So, QB = PC = 41 m In right angle triangle APC, tan P = (𝑆𝑖𝑑𝑒 𝑜𝑝𝑝𝑜𝑠𝑖𝑡𝑒 𝑡𝑜 𝑎𝑛𝑔𝑙𝑒" " 𝑃)/(𝑆𝑖𝑑𝑒 𝑎𝑑𝑗𝑎𝑐𝑒𝑛𝑡 𝑡𝑜 𝑎𝑛𝑔𝑙𝑒" " 𝑃) tan P = AC/PC tan P = 41/41 tan P = 𝟏 Thus, ∠ P = 45° So, required angle of elevation is 45°

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo