This question is similar to Chapter 2 Class 10 Polynomials - Ex 2.2

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https://www.teachoo.com/1489/494/Ex-2.2--1---Find-zeroes-of-following-quadratic-polynomials/category/Ex-2.2/

 

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Question 28 Find the zeroes of the quadratic polynomial 2𝑥2 – (1 + 2√2) 𝑥 + √2 and verify the relationship between the zeroes and coefficients of the polynomial.Let p(x) = 2𝑥2 – (1 + 2√2) 𝑥 + √2 Zero of the polynomial is the value of x where p(x) = 0 Putting p(x) = 0 2𝑥2 – (1 + 2√2) 𝑥 + √2 = 0 We find roots using splitting the middle term method 2x2 – x – 2√𝟐 x + √𝟐 = 0 x(2x – 1) – √2(2x – 1) = 0 Splitting the middle term method We need to find two numbers where Sum = 1 + 2√2 Product = 2 × √2 = 2 √2 (x – √𝟐)(2x − 1) = 0 Thus, our roots are x = √𝟐, and x =𝟏/𝟐 Verifying relationship b/w zeroes and coefficients p(x) = 2𝑥2 – (1 + 2√2) 𝑥 + √2 Comparing with ax2 + bx + c a = 2 , b = –(1 + 2√𝟐), c = √𝟐 We have to verify Sum of zeroes = − (𝐶𝑜𝑒𝑓𝑓𝑖𝑐𝑖𝑒𝑛𝑡 𝑜𝑓 𝑥)/(𝐶𝑜𝑒𝑓𝑓𝑖𝑐𝑖𝑒𝑛𝑡 𝑜𝑓 𝑥2) i.e. α + β = – 𝒃/𝒂 Since, L.H.S = R.H.S Hence relationship between zeroes & coefficient is verified Product of zeroes = (𝐶𝑜𝑛𝑠𝑡𝑎𝑛𝑡 𝑡𝑒𝑟𝑚)/(𝐶𝑜𝑒𝑓𝑓𝑖𝑐𝑖𝑒𝑛𝑡 𝑜𝑓 𝑥2) i.e. α × β = 𝒄/𝒂

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo