Question 21 (A) The A.P 8, 10, 12,……. has 60 terms. Find the sum of last 10 terms.Given AP
8, 10, 12, …, upto 60 terms
Here a = 8
d = 10 – 8 = 2
We need to find the last term, i.e. 60th term
n = 60
Now,
an = a + (n – 1) d
Putting values
an = 8 + (60 – 1) × 2
an = 8 + 59 × 2
an = 8 + 118
an = 126
Thus, last term is 126
Now, we need to find Sum of last 10 terms
Last 10 terms will be from the 51st to the 60th term
Now,
51st term = a51
= a + (n – 1) d
= 8 + (51 – 1) × 2
= 8 + 50 × 2
= 8 + 100
= 108
So, our last 10 terms will be
108, 110, …. 126
This is an AP, with
First term = A = 108
Last term = L = 126
Now,
Sum of n term = 𝒏/𝟐 (A + L)
Putting n = 10, A = 108, L = 126
= 10/2 (108 + 126)
= 5 × 234
= 1,170
∴ Required sum is 1170
Made by
Davneet Singh
Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo
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