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Question 21 (A) The A.P 8, 10, 12,……. has 60 terms. Find the sum of last 10 terms.Given AP 8, 10, 12, …, upto 60 terms Here a = 8 d = 10 – 8 = 2 We need to find the last term, i.e. 60th term n = 60 Now, an = a + (n – 1) d Putting values an = 8 + (60 – 1) × 2 an = 8 + 59 × 2 an = 8 + 118 an = 126 Thus, last term is 126 Now, we need to find Sum of last 10 terms Last 10 terms will be from the 51st to the 60th term Now, 51st term = a51 = a + (n – 1) d = 8 + (51 – 1) × 2 = 8 + 50 × 2 = 8 + 100 = 108 So, our last 10 terms will be 108, 110, …. 126 This is an AP, with First term = A = 108 Last term = L = 126 Now, Sum of n term = 𝒏/𝟐 (A + L) Putting n = 10, A = 108, L = 126 = 10/2 (108 + 126) = 5 × 234 = 1,170 ∴ Required sum is 1170

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo