Question 15 If the probability of the letter chosen at random from the letters of the word "Mathematics" to be a vowel is 2/(2π₯+1), then π₯ is equal to (A) 4/11 (B) 9/4 (C) 11/4 (D) 4/9Word βMATHEMATICS has total 11 letters M, M, A, A, T, T, H, E, I, C, S
Number of letters in word βMATHEMATICSβ = 11
Vowels are a, e, i, o, u
Vowels in in word βMATHEMATICSβ is A, A, E, I
Number of vowels in word βMATHEMATICSβ = 4
Now,
Required Probability = (π΅πππππ ππ ππππππ ππ π€πππ ππ΄ππ»πΈππ΄ππΌπΆπ)/(π΅πππππ ππ πππππππ ππ π€πππ ππ΄ππ»πΈππ΄ππΌπΆπ)
= π/ππ
Now, given that
Required Probability = 2/(2π₯+1)
Putting values
π/ππ = π/(ππ+π)
4(2x + 1) = 2 Γ 11
8x + 4 = 22
8x = 22 β 4
8x = 18
x = 18/8
x = π/π
So, the correct answer is (b)
Made by
Davneet Singh
Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo
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