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Transcript

Question 5 If 𝑠𝑒𝑐 𝛳 + 𝑡𝑎𝑛 𝛳 = 𝑥 ,then 𝑠𝑒𝑐 𝛳 − 𝑡𝑎𝑛 𝛳 will be (A) 𝑥 (B) 𝑥2 (C) 2/𝑥 (D) 1/𝑥We know that, 1 + tan2 𝜃 = sec2 𝜃 1 = sec2 𝜃 – tan2 𝜃 sec2 𝜃 – tan2 𝜃 = 1 Using (a – b) (a + b) = a2 – b2 identity (sec 𝜃 – tan 𝜃) × (sec 𝜃 + tan 𝜃) = 1 Putting values (sec 𝜃 – tan 𝜃) × x = 1 (sec 𝜃 – tan 𝜃) = 𝟏/𝒙 So, the correct answer is (d)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo