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Transcript

Question 3 If the lines given by 3𝑥+2𝑘𝑦=2 and 2𝑥+5𝑦+1=0 are not parallel, then k has to be (A) 15/4 (B) ≠15/4 (C) any rational number (D) any rational number having 4 as denominator3x + 2ky − 2 = 0 Comparing with a1x + b1y + c1 = 0 ∴ a1 = 3 , b1 = 2k , c1 = −2 2x + 5y + 1 = 0 Comparing with a2x + b2y + c2 = 0 ∴ a2 = 2 , b2 = 5, c2 = 1 𝑎1/𝑎2 = 3/2 𝑏1/𝑏2 = 2𝑘/5 𝑐1/𝑐2 = (−2)/1 𝑐1/𝑐2 = −2 Since the lines are not parallel 𝒂𝟏/𝒂𝟐 ≠ 𝒃𝟏/𝒃𝟐 3/2≠2𝑘/5 Therefore, a1 = 3 , b1 = 2k , c1 = −2 & a2 = 2 , b2 = 5, c2 = 1 3/2 × 5/2 ≠ k k ≠ 𝟏𝟓/𝟒 So, the correct answer is (b)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo