Question 37 (ii) - If DP= 50 cm and PE = 70 cm then find PQ/EF - CBSE Class 10 Sample Paper for 2025 Boards - Maths Standard

part 2 - Question 37 (ii) - CBSE Class 10 Sample Paper for 2025 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards - Class 10
part 3 - Question 37 (ii) - CBSE Class 10 Sample Paper for 2025 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards - Class 10

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Question 37 (ii) (ii) If DP = 50 cm and PE = 70 cm then find 𝑃𝑄/𝐸𝐹.Since Ξ” DPQ ~ Ξ” DEF And, we know that Sides of similar triangles are proportional Therefore, 𝑫𝑷/𝑫𝑬=𝑷𝑸/𝑬𝑭 Since we know DP and PE, putting DE = DP + PE 𝐷𝑃/(𝐷𝑃 + 𝑃𝐸)=𝑃𝑄/𝐸𝐹 Putting DP = 50 cm and PE = 70 cm 50/(50 + 70)=𝑃𝑄/𝐸𝐹 50/120=𝑃𝑄/𝐸𝐹 5/12=𝑃𝑄/𝐸𝐹 𝑷𝑸/𝑬𝑭=πŸ“/𝟏𝟐

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo