Check sibling questions

Example 24 - In how many ways can 5 girls and 3 boys be seated

Example 24 - Chapter 7 Class 11 Permutations and Combinations - Part 2

This video is only available for Teachoo black users

Introducing your new favourite teacher - Teachoo Black, at only ₹83 per month


Transcript

Example 24 In how many ways can 5 girls and 3 boys be seated in a row so that no two boys are together? The seating arrangement would be as follows Hence total number of ways they can sit = 120 × 120 = 14400 ways 5 girls can sit in any of 5 places Number of ways they can sit = 5P5 = 5!/(5 − 5)! = 5!/0! = 5!/1 = 5 × 4 × 3 × 2 × 1 = 120 3 boys can sit at any of 6 places marked Number of ways they can sit = 6P3 = 6!/(6 − 3)! = 6!/3! = (6 × 5 × 4 × 3!)/3! = 120

Davneet Singh's photo - Teacher, Engineer, Marketer

Made by

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.