Example 24 - In how many ways can 5 girls and 3 boys be seated - Permutation- non repeating

  1. Chapter 7 Class 11 Permutations and Combinations
  2. Serial order wise
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Example 24 In how many ways can 5 girls and 3 boys be seated in a row so that no two boys are together? The seating arrangement would be as follows 5 girls can sit in any of 5 places Number of ways they can sit = 5P5 = 5!/( 5 − 5)! = 5!/0! = 5!/1 = 5 × 4 × 3 × 2 × 1 = 120 ways Hence total number of ways they can sit = 120 × 120 = 14400 ways

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