Ex 6.3,1 - Chapter 6 Class 11 Permutations and Combinations

Last updated at Dec. 16, 2024 by

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Ex 6.3, 1 (Method 1) How many 3-digit numbers can be formed by using the digits 1 to 9 if no digit is repeated? Let the 3-digit number be Number of 3 digit number which can be formed = 9 × 8 × 7 = 504 ways Ex 6.3, 1 (Method 2) How many 3-digit numbers can be formed by using the digits 1 to 9 if no digit is repeated? Given n = numbers from 1 to 9 = 9 r = 3 Required 3 digit numbers = 9P3 = 9!/(9 − 3)! = 9!/6! = (9 × 8 × 7 × 6!)/6! = 9 × 8 × 7 = 504

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo