Example 22 - Find number of words of AGAIN. What will be 50th word - Permutation- repeating

  1. Chapter 7 Class 11 Permutations and Combinations
  2. Serial order wise

Transcript

Example 22 Find the number of words with or without meaning which can be made using all the letters of the word AGAIN. If these words are written as in a dictionary, what will be the 50th word? ‘AGAIN’ = 2A, 1G, 1I & 1N In dictionary, letters appear alphabetically, Total no of words starting with A, G, & I = 24 + 12 + 12 = 48 Hence 49th word will be start from N i.e. N A A G I & remaining four rearrange according to a dictionary The 50th words is N A A I G Hence the 50th words will be NAAIG

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.