Example 21 - A group consists of 4 girls and 7 boys. In how many - Combination

  1. Chapter 7 Class 11 Permutations and Combinations
  2. Serial order wise
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Example 21 A group consists of 4 girls and 7 boys. In how many ways can a team of 5 members be selected if the team has no girl ? Total number of ways = 4C0 7C5 = 4!/0!(4 0)! 7!/5!(7 5)! = 4!/(1 (4)!) 7!/5!2! = 1 (7 6 5!)/(5! 2 1) = (7 6)/2 = 21 Example, 21 A group consists of 4 girls and 7 boys. In how many ways can a team of 5 members be selected if the team has (ii) at least one boy and one girl ? A group giving at least one boy & one girl will consist of Option 1 1 boys, and 4 girls Option 2 2 boys, and 3 girls Option 3 3 boys, and 2 girls Option 4 4 boys, and 1 girls Option 1 If a group consist of 1 boys & 4 girls No of ways selecting 1 boys & 4 girls = 7C1 4C4 = 7!/1!(7 1)! 4!/4!(4 4)! = 7!/1!6! 4!/4!0! = 7!/1!6! 4!/4!1 = (7 6!)/6! 4!/4! = 7 1 = 7 Option 2 If there are 2 boys & 3 girls Number of ways selecting 2 boys and 3 girls = 7C2 4C3 = 7!/2!(7 2)! 4!/3!(4 3)! = 7!/2!5! 4!/3!1! = (7 6 5!)/(2 1 5!) (4 3!)/(3! 1) = (7 6)/(2 1) 4/1 = 84 ways Option 3 If there are 3 boys & 2 girls No of ways selecting 3 boys & 2 girls = 7C3 4C2 = 7!/3!(7 3)! 4!/2!(4 2)! = 7!/3!4! 4!/2!2! = (7 6 5 4!)/(3 2 1 4!) (4 3 2!)/(2! 2 1) = (7 6 5)/(3 2 1) (4 3)/(2 1) = 210 ways Option 4 If there are 4 boys & 1 girl No of ways selecting 4 boys & 1 girls = 7C4 4C1 = 7!/4!(7 4)! 4!/1!(4 1)! = 7!/4!3! 4!/1!3! = (7 6 5 4!)/(3 2 1 4!) (4 3!)/(3! 1) = (7 6 5)/(3 2 1) (4 )/1 = 140 ways Hence, total number of ways = 7 + 84 + 210 + 140 = 441 ways Example, 21 A group consists of 4 girls and 7 boys. In how many ways can a team of 5 members be selected if the team has (iii) at least 3 girls ? Since, the team has to consist of at least 3 girls, the team can consist of 3 girls and 2 boys 4 girls and 1 boy. Option 1 3 girls & 2 boys No of ways selecting = 7C2 4C3 = 7!/2!(7 2)! 4!/3!(4 3)! = 7!/2!5! 4!/3!1! = (7 6 5!)/(2 1 5!) (4 3!)/(3! 1) = (7 6 4)/(2 1) = 84 Option 2 4 girls & 1 boys No of ways selecting = 7C1 4C4 = 7!/1!(7 1)! 4!/4!(4 4)! = 7!/1!6! 4!/4!0! = 7!/1!6! 4!/4!1 = (7 6!)/6! 4!/4! = 7 1 = 7 Total number of ways = 84 + 7 = 91

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.