Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
Example 18 - Chapter 6 Class 11 Permutations and Combinations
Last updated at May 29, 2023 by Teachoo
Examples
Example 1
Example 2
Example 3 Important
Example 4 Important
Example 5
Example 6 (i)
Example 6 (ii)
Example 7
Example 8 Important
Example 9 Important
Example 10
Example 11 Important
Example 12 (i) Important
Example 12 (ii)
Example 13
Example 14 Important
Example 15
Example 16 Important
Example 17
Example 18 You are here
Example 19 Important
Example 20 Important
Example 21 Important
Example 22 Important
Example 23 Important
Example 24 Important
Chapter 6 Class 11 Permutations and Combinations
Serial order wise
- Ex 6.1
- Ex 6.2
- Ex 6.3
- Ex 6.4
-
Examples
- Miscellaneous
Transcript
Example, 18 A committee of 3 persons is to be constituted from a group of 2 men and 3 women. In how many ways can this be done? How many of these committees would consist of 1 man and 2 women? We have to select a committee of 5 different person taken 3 at a time Here, n = 5 r = 3 The required number of ways = nCr = 5C3 = 5!/3!(5 −3)! = 5!/3!2! = (5 × 4 × 3!)/(3! ×(2 × 1)) = 5 × 2 = 10 ways Total 2 men and 3 women Committees would consist of 1 man and 2 women Now we have to select 1 man from 2 men So, n = 2 r = 1 Number of ways = 2C1 = 2!/1!(2 −1)! = 2!/1!1! = 2 Number of ways to select 1 man & 2 women = 2 × 3 = 6 ways
