Example 9 - Chapter 6 Class 11 Permutations and Combinations
Last updated at April 16, 2024 by Teachoo
Examples
Example 1
Example 2
Example 3 Important
Example 4 Important
Example 5
Example 6 (i)
Example 6 (ii)
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Example 9 Important You are here
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Example 11 Important
Example 12 (i) Important
Example 12 (ii)
Example 13
Example 14 Important
Example 15
Example 16 Important
Example 17
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Example 19 Important
Example 20 Important
Example 21 Important
Example 22 Important
Example 23 Important
Example 24 Important
Chapter 6 Class 11 Permutations and Combinations
Serial order wise
- Ex 6.1
- Ex 6.2
- Ex 6.3
- Ex 6.4
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Examples
- Miscellaneous
Transcript
Example 9 Find the number of permutations of the letters of the word ALLAHABAD. In ALLAHABAD There are 4A , 2L , 1H, 1B & 1D Since alphabets are repeating we will us this formula !/ 1! 2! 3! Total number of alphabets = 9 Here n = 9 , There are 4A s, 2L s hence taking p1 = 4 & p2 = 2 Hence total number of permutation = !/ 1! 2! = 9!/4!2! = (9 8 7 6 5 4!)/((2 1) 4!) = (9 8 7 6 5 )/2 = 7560
