Example 9 - Find number of permutations of ALLAHABAD - Examples

  1. Chapter 7 Class 11 Permutations and Combinations
  2. Serial order wise
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Example 9 Find the number of permutations of the letters of the word ALLAHABAD. In ALLAHABAD There are 4A , 2L , 1H, 1B & 1D Since alphabets are repeating we will us this formula ๐‘›!/๐‘1!๐‘2!๐‘3! Total number of alphabets = 9 Here n = 9 , There are 4Aโ€™s, 2Lโ€™s hence taking p1 = 4 & p2 = 2 Hence total number of permutation = ๐‘›!/๐‘1!๐‘2! = 9!/4!2! = (9 ร— 8 ร— 7 ร— 6 ร— 5ร— 4!)/((2 ร— 1) ร— 4!) = (9 ร— 8 ร— 7 ร— 6 ร— 5 )/2 = 7560

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.