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Ex 15.1, 25 (i) - Chapter 15 Class 10 Probability (Term 1)

Last updated at Aug. 13, 2021 by

Ex 15.1, 25 - (i) If two coins are tossed, there are three - Ex 15.1

Ex 15.1, 25 - Chapter 15 Class 10 Probability - Part 2

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Ex 15.1, 25 Which of the following arguments are correct and which are not correct? Give reasons for your answer. (i) If two coins are tossed simultaneously, there are three possible outcomes, two heads, two tails or one of each. For each of these outcomes, the probability is 1/3 Total possible outcomes = (H, H) , (H, T), (T, H), (T, T) Number of possible outcomes = 4 Probability of getting two heads = (π‘π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘‘π‘–π‘šπ‘’π‘  π‘‘π‘€π‘œ β„Žπ‘’π‘Žπ‘‘π‘  π‘œπ‘π‘π‘’π‘Ÿπ‘ )/(π‘‡π‘œπ‘‘π‘Žπ‘™ π‘›π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘œπ‘’π‘‘π‘π‘œπ‘šπ‘’π‘ ) Probability of getting two tails = (π‘π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘‘π‘–π‘šπ‘’π‘  π‘‘π‘€π‘œ π‘‘π‘Žπ‘–π‘™π‘  π‘œπ‘π‘π‘’π‘Ÿπ‘ )/(π‘‡π‘œπ‘‘π‘Žπ‘™ π‘›π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘œπ‘’π‘‘π‘π‘œπ‘šπ‘’π‘ ) Probability of getting one head & one tails = (π‘π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘‘π‘–π‘šπ‘’π‘  π‘œπ‘›π‘’ β„Žπ‘’π‘Žπ‘‘ π‘Žπ‘›π‘‘ π‘œπ‘›π‘’ π‘‘π‘Žπ‘–π‘™ π‘œπ‘π‘π‘’π‘Ÿπ‘ )/(π‘‡π‘œπ‘‘π‘Žπ‘™ π‘›π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘œπ‘’π‘‘π‘π‘œπ‘šπ‘’π‘ ) = 2/4 = 1/2 Therefore the given statement is incorrect. The probabilities of these outcomes is not 1/3

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