Last updated at Dec. 8, 2016 by Teachoo

Transcript

Ex15.1, 14 One card is drawn from a well-shuffled deck of 52 cards. Find the probability of getting (i) a king of red colour Total number of cards = 52 Total number of kings of red colour = 2 P (getting a king of red colour) = (𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑘𝑖𝑛𝑔 𝑐𝑎𝑟𝑑𝑠 𝑜𝑓 𝑟𝑒𝑑 𝑐𝑜𝑙𝑜𝑢𝑟)/(𝑇𝑜𝑡𝑎𝑙 𝑛𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑐𝑎𝑟𝑑𝑠) = 2/52 = 1/26 Ex15.1, 14 One card is drawn from a well-shuffled deck of 52 cards. Find the probability of getting (ii) a face card Total number of cards = 52 Face cards are King, Queen and Jack Each type has 4 cards Total number of face cards = 3 × 4 = 12 P (getting a face card) = (𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑓𝑎𝑐𝑒 𝑐𝑎𝑟𝑑𝑠)/(𝑇𝑜𝑡𝑎𝑙 𝑛𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑐𝑎𝑟𝑑𝑠) = 12/52 = 3/13 Ex15.1, 14 One card is drawn from a well-shuffled deck of 52 cards. Find the probability of getting (iii) A red face card Total number of cards = 52 Face cards are King, Queen and Jack Total number Red of face cards = 6 P (getting a red face card) = (𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑟𝑒𝑑 𝑓𝑎𝑐𝑒 𝑐𝑎𝑟𝑑𝑠)/(𝑇𝑜𝑡𝑎𝑙 𝑛𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑐𝑎𝑟𝑑𝑠) = 6/52 = 3/26 Ex15.1, 14 One card is drawn from a well-shuffled deck of 52 cards. Find the probability of getting (iv) the jack of hearts Total number of cards = 52 We have 4 Jack cards Total number of Jack of hearts = 1 P (getting a Jack of hearts) = (𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝐽𝑎𝑐𝑘 𝑜𝑓 ℎ𝑒𝑎𝑟𝑡𝑠 𝑐𝑎𝑟𝑑𝑠)/(𝑇𝑜𝑡𝑎𝑙 𝑛𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑐𝑎𝑟𝑑𝑠) = 1/52 Ex15.1, 14 One card is drawn from a well-shuffled deck of 52 cards. Find the probability of getting (v) a spade Total number of cards = 52 We have 4 suits – spade, club, diamond and hearts. Total number of spade cards = 13 P (getting a spade card) = (𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑠𝑝𝑎𝑑𝑒 𝑐𝑎𝑟𝑑𝑠)/(𝑇𝑜𝑡𝑎𝑙 𝑛𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑐𝑎𝑟𝑑𝑠) = 13/52 = 1/4 Ex15.1, 14 One card is drawn from a well-shuffled deck of 52 cards. Find the probability of getting (vi) the queen of diamonds Total number of cards = 52 We have 4 queen cards Total number of queen of diamonds = 1 P (getting a queen of diamond) = (𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑞𝑢𝑒𝑒𝑛 𝑜𝑓 𝑑𝑖𝑎𝑚𝑜𝑛𝑑𝑠)/(𝑇𝑜𝑡𝑎𝑙 𝑛𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑐𝑎𝑟𝑑𝑠) = 1/52

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Ex 15.1, 4 Important

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Ex 15.1, 14 You are here

Ex 15.1, 15 Important

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Ex 15.1, 19 Important

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Ex 15.1, 24 Important

Ex 15.1, 25 Important

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 7 years. He provides courses for Mathematics and Science from Class 6 to 12. You can learn personally from here https://www.teachoo.com/premium/maths-and-science-classes/.