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Ex 15.1, 10 - A piggy bank contains hundred 50 p coins, fifty - Bag/ Box / Piggy bank

  1. Chapter 15 Class 10 Probability
  2. Serial order wise
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Ex15.1, 10 A piggy bank contains hundred 50 p coins, fifty Rs 1 coins, twenty Rs 2 coins and ten Rs 5 coins. If it is equally likely that one of the coins will fall out when the bank is turned upside down, what is the probability that the coin will be a 50 p coin? Total number of coins in a piggy bank = 100 + 50 + 20 + 10 = 180 Number of 50 p coins = 100 Probability of getting a 50 p coin = (𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑐𝑜𝑖𝑛𝑠 𝑜𝑓 50𝑝)/(𝑇𝑜𝑡𝑎𝑙 𝑛𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑐𝑜𝑖𝑛𝑠) = 100/180 = 5/9 Ex15.1, 10 A piggy bank contains hundred 50 p coins, fifty Rs 1 coins, twenty Rs 2 coins and ten Rs 5 coins. If it is equally likely that one of the coins will fall out when the bank is turned upside down, what is the probability that the coin (ii) will not be a ₹ 5 coin? Total number of coins in a piggy bank = 180 Number of ₹ 5 coins = 10 P(not getting a ₹ 5 coin) = 1 – P(getting a ₹ 5 coin) P(getting a ₹ 5 coin) = (𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑐𝑜𝑖𝑛𝑠 𝑜𝑓 ₹ 5 )/(𝑇𝑜𝑡𝑎𝑙 𝑛𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑐𝑜𝑖𝑛𝑠) = 10/180 = 1/18 P(not getting a ₹ 5 coin) = 1 – P(getting a ₹ 5 coin) = 1 – 1/18 = 17/18

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He provides courses for Mathematics from Class 9 to 12. You can ask questions here.
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