Ex 15.1
Ex 14.1, 2 Important
Ex 14.1, 3
Ex 14.1, 4 (MCQ) Important
Ex 14.1, 5
Ex 14.1, 6 Important
Ex 14.1, 7
Ex 14.1, 8
Ex 14.1, 9
Ex 14.1, 10 You are here
Ex 14.1, 11
Ex 14.1, 12 Important
Ex 14.1, 13
Ex 14.1, 14 Important
Ex 14.1, 15 Important
Ex 14.1, 16
Ex 14.1, 17
Ex 14.1, 18 Important
Ex 14.1, 19 Important
Ex 14.1, 20* (Optional) Important
Ex 14.1, 21
Ex 14.1, 22 Important
Ex 14.1, 23
Ex 14.1, 24 Important
Ex 14.1, 25 (i) Important
Ex 14.1, 25 (ii)
Last updated at April 16, 2024 by Teachoo
You saved atleast 2 minutes by viewing the ad-free version of this page. Thank you for being a part of Teachoo Black.
Ex 14.1, 10 A piggy bank contains hundred 50 p coins, fifty Rs 1 coins, twenty Rs 2 coins and ten Rs 5 coins. If it is equally likely that one of the coins will fall out when the bank is turned upside down, what is the probability that the coin will be a 50 p coin? Total number of coins in a piggy bank = 100 + 50 + 20 + 10 = 180 Number of 50 p coins = 100 Probability of getting a 50 p coin = (𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑐𝑜𝑖𝑛𝑠 𝑜𝑓 50𝑝)/(𝑇𝑜𝑡𝑎𝑙 𝑛𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑐𝑜𝑖𝑛𝑠) = 100/180 = 𝟓/𝟗 Ex 14.1, 10 A piggy bank contains hundred 50 p coins, fifty Rs 1 coins, twenty Rs 2 coins and ten Rs 5 coins. If it is equally likely that one of the coins will fall out when the bank is turned upside down, what is the probability that the coin (ii) will not be a ₹ 5 coin? Total number of coins in a piggy bank = 180 Number of ₹ 5 coins = 10 P(not getting a ₹ 5 coin) = 1 – P(getting a ₹ 5 coin) Now, P(getting a ₹ 5 coin) = (𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑐𝑜𝑖𝑛𝑠 𝑜𝑓 ₹ 5 )/(𝑇𝑜𝑡𝑎𝑙 𝑛𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑐𝑜𝑖𝑛𝑠) = 10/180 = 𝟏/𝟏𝟖 Thus, P(not getting a ₹ 5 coin) = 1 – P(getting a ₹ 5 coin) = 1 – 1/18 = 𝟏𝟕/𝟏𝟖