Ex 15.1, 7
Last updated at Dec. 8, 2016 by Teachoo
Transcript
Ex15.1, 7 It is given that in a group of 3 students, the probability of 2 students not having the same birthday is 0.992. What is the probability that the 2 students have the same birthday? Probability that two students are not having same birthday = 0.992 Probability that two students are not having same birthday = 1 – Probability that two students are having same birthday P(not same birthday) = 1 – P(same birthday) 0.992 = 1 – P(same birthday) P(same birthday) = 1 – 0.992 P(same birthday) = 0.008 So, probability that 2 students will have the same birthday is 0.008
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