Last updated at June 29, 2018 by Teachoo

Transcript

Ex15.1, 13 A die is thrown once. Find the probability of getting (i) a prime number; Total outcomes that can occur are 1, 2, 3, 4, 5, 6 Number of possible outcomes of a dice = 6 Prime number is a number not divisible by any number except itself Prime numbers on a dice are 2, 3, and 5. Total prime numbers on a dice = 3 Probability of getting a prime number = (๐๐ข๐๐๐๐ ๐๐ ๐๐ข๐ก๐๐๐๐๐ ๐คโ๐๐๐ ๐๐๐๐๐ ๐๐ข๐๐๐๐ ๐๐๐๐๐ )/(๐๐๐ก๐๐ ๐๐ข๐๐๐๐ ๐๐ ๐๐ข๐ก๐๐๐๐๐ ) = 3/6 = 1/2 Ex15.1, 13 A die is thrown once. Find the probability of getting (ii) a number lying between 2 and 6; Total outcomes that can occur are 1, 2, 3, 4, 5, 6 Number of possible outcomes of a dice = 6 Numbers lying between 2 and 6 = 3, 4, 5 Total numbers lying between 2 and 6 = 3 Probability of getting a number lying between 2 & 6 = (๐๐ข๐๐๐๐ ๐๐ ๐๐ข๐ก๐๐๐๐๐ ๐คโ๐๐๐ ๐กโ๐๐๐ ๐๐ ๐ ๐๐ข๐๐๐๐ ๐๐๐ก๐ค๐๐๐ 2 & 6)/(๐๐๐ก๐๐ ๐๐ข๐๐๐๐ ๐๐ ๐๐ข๐ก๐๐๐๐๐ ) = 3/6 = 1/2 Ex15.1, 13 A die is thrown once. Find the probability of getting (iii) an odd number. Total outcomes that can occur are 1, 2, 3, 4, 5, 6 Number of possible outcomes of a dice = 6 Numbers which are odd = 1,3, 5 Total numbers which are odd = 3 Probability of getting an odd number = (๐๐ข๐๐๐๐ ๐๐ ๐๐ข๐ก๐๐๐๐๐ ๐คโ๐๐๐ ๐กโ๐๐๐ ๐๐ ๐๐ ๐๐๐ ๐๐ข๐๐๐๐)/(๐๐๐ก๐๐ ๐๐ข๐๐๐๐ ๐๐ ๐๐ข๐ก๐๐๐๐๐ ) = 3/6 = 1/2

Ex 15.1

Ex 15.1, 1

Ex 15.1, 2

Ex 15.1, 3

Ex 15.1, 4 Important

Ex 15.1, 5

Ex 15.1, 6 Important

Ex 15.1, 7

Ex 15.1, 8

Ex 15.1, 9

Ex 15.1, 10

Ex 15.1, 11

Ex 15.1, 12

Ex 15.1, 13 You are here

Ex 15.1, 14

Ex 15.1, 15 Important

Ex 15.1, 16

Ex 15.1, 17

Ex 15.1, 18

Ex 15.1, 19 Important

Ex 15.1, 20* (Optional)

Ex 15.1, 21

Ex 15.1, 22

Ex 15.1, 23

Ex 15.1, 24 Important

Ex 15.1, 25 Important

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.