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Ex 15.1
Ex 15.1, 2 Important
Ex 15.1, 3
Ex 15.1, 4 (MCQ) Important
Ex 15.1, 5
Ex 15.1, 6 Important
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Ex 15.1, 8
Ex 15.1, 9
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Ex 15.1, 11
Ex 15.1, 12 Important
Ex 15.1, 13 You are here
Ex 15.1, 14 Important
Ex 15.1, 15 Important
Ex 15.1, 16
Ex 15.1, 17
Ex 15.1, 18 Important
Ex 15.1, 19 Important
Ex 15.1, 20* (Optional) Important
Ex 15.1, 21
Ex 15.1, 22 Important
Ex 15.1, 23
Ex 15.1, 24 Important
Ex 15.1, 25 (i) Important
Ex 15.1, 25 (ii)
Last updated at June 29, 2018 by Teachoo
Ex15.1, 13 A die is thrown once. Find the probability of getting (i) a prime number; Total outcomes that can occur are 1, 2, 3, 4, 5, 6 Number of possible outcomes of a dice = 6 Prime number is a number not divisible by any number except itself Prime numbers on a dice are 2, 3, and 5. Total prime numbers on a dice = 3 Probability of getting a prime number = (ππ’ππππ ππ ππ’π‘πππππ π€βπππ πππππ ππ’ππππ πππππ )/(πππ‘ππ ππ’ππππ ππ ππ’π‘πππππ ) = 3/6 = 1/2 Ex15.1, 13 A die is thrown once. Find the probability of getting (ii) a number lying between 2 and 6; Total outcomes that can occur are 1, 2, 3, 4, 5, 6 Number of possible outcomes of a dice = 6 Numbers lying between 2 and 6 = 3, 4, 5 Total numbers lying between 2 and 6 = 3 Probability of getting a number lying between 2 & 6 = (ππ’ππππ ππ ππ’π‘πππππ π€βπππ π‘βπππ ππ π ππ’ππππ πππ‘π€πππ 2 & 6)/(πππ‘ππ ππ’ππππ ππ ππ’π‘πππππ ) = 3/6 = 1/2 Ex15.1, 13 A die is thrown once. Find the probability of getting (iii) an odd number. Total outcomes that can occur are 1, 2, 3, 4, 5, 6 Number of possible outcomes of a dice = 6 Numbers which are odd = 1,3, 5 Total numbers which are odd = 3 Probability of getting an odd number = (ππ’ππππ ππ ππ’π‘πππππ π€βπππ π‘βπππ ππ ππ πππ ππ’ππππ)/(πππ‘ππ ππ’ππππ ππ ππ’π‘πππππ ) = 3/6 = 1/2