Ex 15.1

Chapter 14 Class 10 Probability
Serial order wise

### Transcript

Ex 14.1, 13 A die is thrown once. Find the probability of getting (i) a prime number; Total outcomes that can occur are 1, 2, 3, 4, 5, 6 Number of possible outcomes of a dice = 6 Prime number is a number not divisible by any number except itself Prime numbers on a dice are 2, 3, and 5. Total prime numbers on a dice = 3 Probability of getting a prime number = (๐๐ข๐๐๐๐ ๐๐ ๐๐ข๐ก๐๐๐๐๐  ๐คโ๐๐๐ ๐๐๐๐๐ ๐๐ข๐๐๐๐ ๐๐๐๐๐ )/(๐๐๐ก๐๐ ๐๐ข๐๐๐๐ ๐๐ ๐๐ข๐ก๐๐๐๐๐ ) = 3/6 = ๐/๐ Ex 14.1, 13 A die is thrown once. Find the probability of getting (ii) a number lying between 2 and 6; Total outcomes that can occur are 1, 2, 3, 4, 5, 6 Number of possible outcomes of a dice = 6 Numbers lying between 2 and 6 = 3, 4, 5 Total numbers lying between 2 and 6 = 3 Probability of getting a number lying between 2 & 6 = (๐๐ข๐๐๐๐ ๐๐ ๐๐ข๐ก๐๐๐๐๐  ๐คโ๐๐๐ ๐กโ๐๐๐ ๐๐  ๐ ๐๐ข๐๐๐๐ ๐๐๐ก๐ค๐๐๐ 2 & 6)/(๐๐๐ก๐๐ ๐๐ข๐๐๐๐ ๐๐ ๐๐ข๐ก๐๐๐๐๐ ) = 3/6 = ๐/๐ Ex 14.1, 13 A die is thrown once. Find the probability of getting (iii) an odd number. Total outcomes that can occur are 1, 2, 3, 4, 5, 6 Number of possible outcomes of a dice = 6 Numbers which are odd = 1,3, 5 Total numbers which are odd = 3 Probability of getting an odd number = (๐๐ข๐๐๐๐ ๐๐ ๐๐ข๐ก๐๐๐๐๐  ๐คโ๐๐๐ ๐กโ๐๐๐ ๐๐  ๐๐ ๐๐๐ ๐๐ข๐๐๐๐)/(๐๐๐ก๐๐ ๐๐ข๐๐๐๐ ๐๐ ๐๐ข๐ก๐๐๐๐๐ ) = 3/6 = ๐/๐