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Ex 15.1, 21 - Chapter 15 Class 10 Probability (Term 1)
Last updated at Dec. 8, 2016 by Teachoo
Ex 15.1
Ex 15.1, 1
Ex 15.1, 2 Important
Ex 15.1, 3
Ex 15.1, 4 (MCQ) Important
Ex 15.1, 5
Ex 15.1, 6 Important
Ex 15.1, 7
Ex 15.1, 8
Ex 15.1, 9
Ex 15.1, 10
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Ex 15.1, 12 Important
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Ex 15.1, 14 Important
Ex 15.1, 15 Important
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Ex 15.1, 17
Ex 15.1, 18 Important
Ex 15.1, 19 Important
Ex 15.1, 20* (Optional) Important
Ex 15.1, 21 You are here
Ex 15.1, 22 Important
Ex 15.1, 23
Ex 15.1, 24 Important
Ex 15.1, 25 (i) Important
Ex 15.1, 25 (ii)
Chapter 15 Class 10 Probability
Serial order wise
Transcript
Ex15.1, 21 A lot consists of 144 ball pens of which 20 are defective and the others are good. Nuri will buy a pen if it is good, but will not buy if it is defective. The shopkeeper draws one pen at random and gives it to her. What is the probability that She will buy it? Total number of pens = 144 Number of pens Nuri will buy = Number of good pens = Total number pens Number of defective pens = 144 20 = 124 P (Nuri buys a pen) = ( )/( ) = 124/144 = 31/36 Ex15.1, 21 A lot consists of 144 ball pens of which 20 are defective and the others are good. Nuri will buy a pen if it is good, but will not buy if it is defective. The shopkeeper draws one pen at random and gives it to her. What is the probability that (ii) She will not buy it? P(Nuri does not buy a pen) = 1 P(Nuri buys a pen) = 1 31/36 = (36 31)/36 = 5/36
