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Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class


Transcript

Ex 14.1, 12 A game of chance consists of spinning an arrow which comes to rest pointing at one of the numbers 1, 2, 3, 4, 5, 6, 7, 8 (see the given figure), and these are equally likely outcomes. What is the probability that it will point at 8? Total numbers = 8 Number of times we can get 8 = 1 Probability of getting 8 = (𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑡𝑖𝑚𝑒𝑠 𝑤𝑒 𝑐𝑎𝑛 𝑔𝑒𝑡 8)/(𝑇𝑜𝑡𝑎𝑙 𝑛𝑢𝑚𝑏𝑒𝑟𝑠) = 𝟏/𝟖 Ex 14.1, 12 (ii) Odd number? Total numbers = 8 Odd numbers that can be the outcome = 1, 3, 5, 7 Number of odd number = 4 Probability of getting odd number = (𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑜𝑑𝑑 𝑛𝑢𝑚𝑏𝑒𝑟)/(𝑇𝑜𝑡𝑎𝑙 𝑛𝑢𝑚𝑏𝑒𝑟𝑠 ) = 4/8 = 𝟏/𝟐 Ex 14.1, 12 (iii) Number greater than 2? Total numbers = 8 Number greater than 2 = 3, 4, 5, 6, 7, 8 Number of numbers greater than 2 = 6 Probability of getting number greater than 2 = (𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑛𝑢𝑚𝑏𝑒𝑟𝑠 𝑔𝑟𝑒𝑎𝑡𝑒𝑟 𝑡ℎ𝑎𝑛 2)/(𝑇𝑜𝑡𝑎𝑙 𝑛𝑢𝑚𝑏𝑒𝑟𝑠 ) = 6/8 = 𝟑/𝟒 Ex 14.1, 12 (iv) Number less than 9? Total numbers = 8 Number less than 9 = 1, 2, 3, 4, 5, 6, 7, 8 Number of number less than 9 = 8 Probability of getting number less than 9 = (𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑛𝑢𝑚𝑏𝑒𝑟𝑠 𝑙𝑒𝑠𝑠 𝑡ℎ𝑎𝑛 9)/(𝑇𝑜𝑡𝑎𝑙 𝑛𝑢𝑚𝑏𝑒𝑟𝑠 ) = 8/8 = 1

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.