Ex 15.1, 12 - A game of chance consists of spinning an arrow - Ex 15.1

  1. Chapter 15 Class 10 Probability
  2. Serial order wise
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Ex15.1, 12 A game of chance consists of spinning an arrow which comes to rest pointing at one of the numbers 1, 2, 3, 4, 5, 6, 7, 8 (see the given figure), and these are equally likely outcomes. What is the probability that it will point at 8? Total numbers = 8 Number of times we can get 8 = 1 Probability of getting 8 Β = (π‘π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘‘π‘–π‘šπ‘’π‘  𝑀𝑒 π‘π‘Žπ‘› 𝑔𝑒𝑑 8)/(π‘‡π‘œπ‘‘π‘Žπ‘™ π‘›π‘’π‘šπ‘π‘’π‘Ÿπ‘ ) = 1/8 Ex15.1, 12 (ii) Odd number? Total numbers = 8 Odd numbers that can be the outcome = 1, 3, 5, 7 Number of odd number = 4 Probability of getting odd numberΒ = (π‘π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘œπ‘‘π‘‘ π‘›π‘’π‘šπ‘π‘’π‘Ÿ)/(π‘‡π‘œπ‘‘π‘Žπ‘™ π‘›π‘’π‘šπ‘π‘’π‘Ÿπ‘  ) = 4/8 = 1/2 Ex15.1, 12 (iii) Number greater than 2? Total numbers = 8 Number greater than 2 = 3, 4, 5, 6, 7, 8 Number of numbers greater than 2 = 6 Probability of getting number greater than 2 Β = (π‘π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘›π‘’π‘šπ‘π‘’π‘Ÿπ‘  π‘”π‘Ÿπ‘’π‘Žπ‘‘π‘’π‘Ÿ π‘‘β„Žπ‘Žπ‘› 2)/(π‘‡π‘œπ‘‘π‘Žπ‘™ π‘›π‘’π‘šπ‘π‘’π‘Ÿπ‘  ) = 6/8 = 3/4 Ex15.1, 12 (iv) Number less than 9? Total numbers = 8 Number less than 9 = 1, 2, 3, 4, 5, 6, 7, 8 Number of number less than 9 = 8 Probability of getting number less than 9 Β = (π‘π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘›π‘’π‘šπ‘π‘’π‘Ÿπ‘  𝑙𝑒𝑠𝑠 π‘‘β„Žπ‘Žπ‘› 9)/(π‘‡π‘œπ‘‘π‘Žπ‘™ π‘›π‘’π‘šπ‘π‘’π‘Ÿπ‘  ) = 8/8 = 1

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