Ex 15.1

Chapter 14 Class 10 Probability
Serial order wise

### Transcript

Ex 14.1, 12 A game of chance consists of spinning an arrow which comes to rest pointing at one of the numbers 1, 2, 3, 4, 5, 6, 7, 8 (see the given figure), and these are equally likely outcomes. What is the probability that it will point at 8? Total numbers = 8 Number of times we can get 8 = 1 Probability of getting 8 = (๐๐ข๐๐๐๐ ๐๐ ๐ก๐๐๐๐  ๐ค๐ ๐๐๐ ๐๐๐ก 8)/(๐๐๐ก๐๐ ๐๐ข๐๐๐๐๐ ) = ๐/๐ Ex 14.1, 12 (ii) Odd number? Total numbers = 8 Odd numbers that can be the outcome = 1, 3, 5, 7 Number of odd number = 4 Probability of getting odd number = (๐๐ข๐๐๐๐ ๐๐ ๐๐๐ ๐๐ข๐๐๐๐)/(๐๐๐ก๐๐ ๐๐ข๐๐๐๐๐  ) = 4/8 = ๐/๐ Ex 14.1, 12 (iii) Number greater than 2? Total numbers = 8 Number greater than 2 = 3, 4, 5, 6, 7, 8 Number of numbers greater than 2 = 6 Probability of getting number greater than 2 = (๐๐ข๐๐๐๐ ๐๐ ๐๐ข๐๐๐๐๐  ๐๐๐๐๐ก๐๐ ๐กโ๐๐ 2)/(๐๐๐ก๐๐ ๐๐ข๐๐๐๐๐  ) = 6/8 = ๐/๐ Ex 14.1, 12 (iv) Number less than 9? Total numbers = 8 Number less than 9 = 1, 2, 3, 4, 5, 6, 7, 8 Number of number less than 9 = 8 Probability of getting number less than 9 = (๐๐ข๐๐๐๐ ๐๐ ๐๐ข๐๐๐๐๐  ๐๐๐ ๐  ๐กโ๐๐ 9)/(๐๐๐ก๐๐ ๐๐ข๐๐๐๐๐  ) = 8/8 = 1