Last updated at May 29, 2018 by

Transcript

Ex15.1,17 (i) A lot of 20 bulbs contain 4 defective ones. One bulb is drawn at random from the lot. What is the probability that this bulb is defective? Total number of bulbs = 20 Total number of defective bulbs = 4 P (getting a defective bulb) = ( )/( ) = 4/20 = 1/5 Ex15.1,17 (ii) Suppose the bulb drawn in (i) is not defective and is not replaced. Now one bulb is drawn at random from the rest. What is the probability that this bulb is not defective? Total number of bulbs left = 20 1 = 19 Number of defective bulbs = 4 Number of non-defective bulbs = 19 4 = 15 P (getting a non-defective bulb) = ( )/( ) = 15/19

Ex 15.1

Ex 15.1, 1

Ex 15.1, 2 Important

Ex 15.1, 3

Ex 15.1, 4 (MCQ) Important

Ex 15.1, 5

Ex 15.1, 6 Important

Ex 15.1, 7

Ex 15.1, 8

Ex 15.1, 9

Ex 15.1, 10

Ex 15.1, 11

Ex 15.1, 12 Important

Ex 15.1, 13

Ex 15.1, 14 Important

Ex 15.1, 15 Important

Ex 15.1, 16

Ex 15.1, 17 You are here

Ex 15.1, 18 Important

Ex 15.1, 19 Important

Ex 15.1, 20* (Optional) Important

Ex 15.1, 21

Ex 15.1, 22 Important

Ex 15.1, 23

Ex 15.1, 24 Important

Ex 15.1, 25 (i) Important

Ex 15.1, 25 (ii)

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.