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Ex 15.1, 8 - A bag contains 3 red balls and 5 black balls - Ex 15.1

Ex 15.1, 8 - Chapter 15 Class 10 Probability - Part 2


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Ex15.1, 8 A bag contains 3 red balls and 5 black balls. A ball is drawn at random from the bag. What is the probability that the ball drawn is (i) red? Total number of balls in the bag = 5 + 3 = 8 Number of red balls = 3 Probability of getting a red ball = (π‘π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘Ÿπ‘’π‘‘ π‘π‘Žπ‘™π‘™π‘ )/(π‘‡π‘œπ‘‘π‘Žπ‘™ π‘›π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘π‘Žπ‘™π‘™π‘ ) = 3/8 Ex15.1, 8 A bag contains 3 red balls and 5 black balls. A ball is drawn at random from the bag. What is the probability that the ball drawn is (ii) not red? Total number of balls in the bag = 8 Probability of not getting a red ball = Probability of getting blackballs = (π‘π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“π‘π‘™π‘Žπ‘π‘˜ π‘π‘Žπ‘™π‘™π‘ )/(π‘‡π‘œπ‘‘π‘Žπ‘™ π‘›π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘π‘Žπ‘™π‘™π‘ ) = 5/8 Method 2 Probability of not getting red ball = 1 βˆ’ Probability of getting a red ball = 1 – 3/8 = 5/8

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