1. Chapter 15 Class 10 Probability (Term 1)
  2. Serial order wise
  3. Ex 15.1

Ex 15.1, 25 (ii) - Chapter 15 Class 10 Probability (Term 1)

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Ex 15.1, 25 - Chapter 15 Class 10 Probability - Part 3

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Ex 15.1, 25 - Chapter 15 Class 10 Probability - Part 4

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  1. Chapter 15 Class 10 Probability (Term 1)
  2. Serial order wise

    3. Ex 15.1

    Examples →

Transcript

Ex 15.1, 25 Which of the following arguments are correct and which are not correct? Give reasons for your answer. (ii) If a die is thrown, there are two possible outcomes- an odd number or an even number .Therefore the probability of getting an odd number is 1/2 Total outcomes that can occur are 1, 2, 3, 4, 5, 6 Number of possible outcomes of a dice = 6 Numbers which are odd = 1, 3, 5 Total numbers which are odd = 3 Numbers which are even = 2, 4, 6 Total numbers which are even = 3 Probability of getting an odd number = (๐‘๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘œ๐‘ข๐‘ก๐‘๐‘œ๐‘š๐‘’๐‘  ๐‘คโ„Ž๐‘’๐‘Ÿ๐‘’ ๐‘กโ„Ž๐‘’๐‘Ÿ๐‘’ ๐‘–๐‘  ๐‘Ž๐‘› ๐‘œ๐‘‘๐‘‘ ๐‘›๐‘ข๐‘š๐‘๐‘’๐‘Ÿ)/(๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™ ๐‘›๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘œ๐‘ข๐‘ก๐‘๐‘œ๐‘š๐‘’๐‘ ) = 3/6 = 1/2 Hence, the given statement is correct

Chapter 15 Class 10 Probability (Term 1)
Serial order wise

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