Ex 15.1, 19
Last updated at Feb. 25, 2017 by Teachoo
Transcript
Ex15.1, 19 A child has a die whose six faces shows the letters as given below: The die is thrown once. What is the probability of getting A? Total number of faces on the die = 6 Number of faces having A on it = 2 P (getting A) = (𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑓𝑎𝑐𝑒𝑠 ℎ𝑎𝑣𝑖𝑛𝑔 𝐴)/(𝑇𝑜𝑡𝑎𝑙 𝑛𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑓𝑎𝑐𝑒𝑠 𝑜𝑛 𝑑𝑖𝑒) = 2/6 = 1/3 Ex15.1, 19 A child has a die whose six faces shows the letters as given below: The die is thrown once. What is the probability of getting (ii) D? Total number of faces on the die = 6 Number of faces having D on it = 1 P (getting D) = (𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑓𝑎𝑐𝑒𝑠 ℎ𝑎𝑣𝑖𝑛𝑔 𝐷)/(𝑇𝑜𝑡𝑎𝑙 𝑛𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑓𝑎𝑐𝑒𝑠 𝑜𝑛 𝑑𝑖𝑒) = 1/6
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About the Author
CA Maninder Singh
CA Maninder Singh is a Chartered Accountant for the past 8 years. He provides courses for Practical Accounts, Taxation and Efiling at teachoo.com .