Ex 13.2, 11 (ii) - Chapter 13 Class 12 Probability

Last updated at August 19, 2026 by

Ex 13.2, 11 (ii) - Given P(A) = 0.3, P(B) = 0.6, find P(A and not B) - Ex 13.2

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Ex 13.2, 11 Given two independent events A & B such that P(A) = 0.3, P(B) = 0.6. Find (ii) P(A and not B) P(A and not B) = P(A ∩ B’) = P(A) – P(A and B) = P(A) – P(A ∩ B) = 0.30 – 0.18 = 0.12

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