# Ex 13.2, 11 (iv) - Chapter 13 Class 12 Probability (Term 2)

Last updated at Aug. 24, 2021 by Teachoo

Last updated at Aug. 24, 2021 by Teachoo

Transcript

Ex 13.2, 11 Given two independent events A & B such that P(A) = 0.3, P(B) = 0.6. Find (iv) P(neither A nor B) P(neither A nor B) = P(A’ and B’) = P(A’ ∩ B’) = P(A ∪ B)’ = 1 – P(A ∪ B) = 1 – 0.72 = 0.28

Ex 13.2

Ex 13.2, 1

Ex 13.2, 2

Ex 13.2, 3 Important

Ex 13.2, 4

Ex 13.2, 5

Ex 13.2, 6

Ex 13.2, 7 Important

Ex 13.2, 8

Ex 13.2, 9 Important

Ex 13.2, 10 Important

Ex 13.2, 11 (i)

Ex 13.2, 11 (ii) Important

Ex 13.2, 11 (iii)

Ex 13.2, 11 (iv) Important You are here

Ex 13.2, 12

Ex 13.2, 13 Important

Ex 13.2, 14 Important

Ex 13.2, 15 (i)

Ex 13.2, 15 (ii)

Ex 13.2, 15 (iii) Important

Ex 13.2, 16 Important

Ex 13.2, 17 (MCQ)

Ex 13.2, 18 (MCQ) Important

Chapter 13 Class 12 Probability (Term 2)

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.