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Last updated at Dec. 8, 2020 by Teachoo

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Ex 13.2, 13 Two balls are drawn at random with replacement from a box containing 10 black and 8 red balls. Find the Probability that (i) both balls are red.Two balls are drawn with replacement from a box Given Number of black balls in box = 10 Number of red balls in box = 8 Total number of balls in box = 10 + 8 = 18 P(both balls are red) = P(first ball is red) × P(second ball is red given first is red) = 8/18 × 8/18 = 4/9 × 4/9 = 𝟏𝟔/𝟖𝟏 Ex 13.2, 13 Two balls are drawn at random with replacement from a box containing 10 black and 8 red balls. Find the Probability that (ii) first ball is black and second is red.P (first ball is black & second is red) = P(first ball is black) × P(second ball is red given first is black) = 10/18 × 8/18 = 5/9 × 4/9 = 𝟐𝟎/𝟖𝟏 Ex 13.2, 13 Two balls are drawn at random with replacement from a box containing 10 black and 8 red balls. Find the Probability that (iii) one of them is black and other is red.P(one ball is black & other is red) = P(first ball is black & second is red) + P(first ball is red & second is black) = (10/18×8/18)+(8/18×10/18) = 2 × (10/18×8/18) = 𝟒𝟎/𝟖𝟏

Ex 13.2

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Chapter 13 Class 12 Probability

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About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.