Ex 13.2, 10 - Chapter 13 Class 12 Probability

Last updated at April 16, 2024 by

Ex 13.2, 10 - P(A) = 1/2, P(B) = 7/12, P(not A or not B) = 1/4

Ex 13.2, 10 - Chapter 13 Class 12 Probability - Part 2

Transcript

Ex 13.2, 10 Events A and B are such that P (A) = 1/2 , P(B) = 7/12 and P (not A or not B) = 1/4 . State whether A and B are independent ?Given, P(A) = 1/2 , P(B) = 7/12 & P(not A or not B) = 1/4 Now, P(not A or not B) = P(A’ or B’) 1/4 = P(A’ ∪ B’) 1/4 = P(A ∩ B)’ 1/4 = 1 – P(A ∩ B) P(A ∩ B) = 1 – 1/4 P(A ∩ B) = 3/4 Also, P(A) . P(B) = 1/2 × 7/12 = 7/24 ≠ P(A ∩ B) Since, P(A ∩ B) ≠ P(A) . P(B) Therefore, the events A and B are not independent

Ask a doubt
Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.