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Ex 13.2, 3 - Chapter 13 Class 12 Probability
Last updated at Aug. 16, 2023 by Teachoo
Ex 13.2
Ex 13.2, 1
Ex 13.2, 2
Ex 13.2, 3 Important You are here
Ex 13.2, 4
Ex 13.2, 5
Ex 13.2, 6
Ex 13.2, 7 Important
Ex 13.2, 8
Ex 13.2, 9 Important
Ex 13.2, 10 Important
Ex 13.2, 11 (i)
Ex 13.2, 11 (ii) Important
Ex 13.2, 11 (iii)
Ex 13.2, 11 (iv) Important
Ex 13.2, 12
Ex 13.2, 13 Important
Ex 13.2, 14 Important
Ex 13.2, 15 (i)
Ex 13.2, 15 (ii)
Ex 13.2, 15 (iii) Important
Ex 13.2, 16 Important
Ex 13.2, 17 (MCQ)
Ex 13.2, 18 (MCQ) Important
Chapter 13 Class 12 Probability
Serial order wise
Transcript
Ex 13.2, 3 A box of oranges is inspected by examining three randomly selected oranges drawn without replacement. If all the three oranges are good, the box is approved for sale, otherwise, it is rejected. Find the Probability that a box containing 15 oranges out of which 12 are good and 3 are bad ones will be approved for sale.Given Total Number of oranges = 15 Number of Good oranges = 12 Number of Bad oranges = 3 Given that Box is approved for sale if all 3 oranges are good Now, Probability that box is approved for sale = Probability that first orange is good × Probability that second orange is good, given first is good × Probability that third orange is good, given first two are good = 12/15 × 𝟏𝟏/𝟏𝟒 × 𝟏𝟎/𝟏𝟑 = 44/91
