1. Chapter 13 Class 12 Probability (Term 2)
  2. Serial order wise
  3. Ex 13.2

Ex 13.2, 9 - Chapter 13 Class 12 Probability (Term 2)

Last updated at Feb. 15, 2020 by

Ex 13.2, 9 - If A and B are two events such that P(A) = 1/4, P(B) =1/4

Ex 13.2, 9 - Chapter 13 Class 12 Probability - Part 2

  1. Chapter 13 Class 12 Probability (Term 2)
  2. Serial order wise

    3. Ex 13.2

    Ex 13.3 →

Transcript

Ex 13.2, 9 If A and B are two events such that P (A) = 1/4 , P (B) = 1/4 and P(A ∩ B) = 1/8 , find P (not A and not B).Given, P(A) = 1/4 , P(B) = 1/2 & P(A ∩ B) = 1/8 P(not A & not B) = P(A’ ∩ B’) = P(A ∪ B)’ = 1 – P(A or B) = 1 – P(A ∪ B) = 1 – [P(A) + P(B) – P(A ∩ B)] = 1 – (1/4 " + " 1/2 – 1/8) As A’ ∩ B’ = (A ∪ B)’ = 1 – (2/8 " + " 4/8 – 1/8) = 1 – 5/8 = 𝟑/𝟖

Chapter 13 Class 12 Probability (Term 2)
Serial order wise

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