Slide21.JPG

Slide22.JPG

Subscribe to our Youtube Channel - https://you.tube/teachoo

  1. Chapter 13 Class 12 Probability
  2. Serial order wise

Transcript

Ex 13.2, 9 If A and B are two events such that P (A) = 1/4 , P (B) = 1/4 and P(A ∩ B) = 1/8 , find P (not A and not B).Given, P(A) = 1/4 , P(B) = 1/2 & P(A ∩ B) = 1/8 P(not A & not B) = P(A’ ∩ B’) = P(A ∪ B)’ = 1 – P(A or B) = 1 – P(A ∪ B) = 1 – [P(A) + P(B) – P(A ∩ B)] = 1 – (1/4 " + " 1/2 – 1/8) As A’ ∩ B’ = (A ∪ B)’ = 1 – (2/8 " + " 4/8 – 1/8) = 1 – 5/8 = 𝟑/𝟖

About the Author

Davneet Singh's photo - Teacher, Computer Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.