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Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
Ex 13.2
Ex 13.2, 2
Ex 13.2, 3 Important
Ex 13.2, 4
Ex 13.2, 5
Ex 13.2, 6
Ex 13.2, 7 Important You are here
Ex 13.2, 8
Ex 13.2, 9 Important
Ex 13.2, 10 Important
Ex 13.2, 11 (i)
Ex 13.2, 11 (ii) Important
Ex 13.2, 11 (iii)
Ex 13.2, 11 (iv) Important
Ex 13.2, 12
Ex 13.2, 13 Important
Ex 13.2, 14 Important
Ex 13.2, 15 (i)
Ex 13.2, 15 (ii)
Ex 13.2, 15 (iii) Important
Ex 13.2, 16 Important
Ex 13.2, 17 (MCQ)
Ex 13.2, 18 (MCQ) Important
Last updated at Aug. 16, 2023 by Teachoo
Ex 13.2, 7 (i) Given that the events A and B are such that P(A) = 1/2 , P (A ∪ B) = 3/5 and P(B) = p. Find p if they are (i) mutually exclusiveGiven, P(A) = 1/2 , P (A ∪ B) = 3/5 and P(B) = p. Since sets A & B are mutually exclusive, So, they have nothing in common ∴ P(A ∩ B) = 0 We know that P(A ∪ B) = P(A) + P(B) – P(A ∩ B) Putting values 3/5 = 1/2 + p – 0 3/5 – 1/2 = p (6 − 5)/10 = p 1/10 = p p = 𝟏/𝟏𝟎 Ex 13.2, 7 (ii) Given that the events A and B are such that P(A) = 1/2 , P (A ∪ B) = 3/5 and P(B) = p. Find p if they are (ii) independent.Since events A & B are independent, So, P(A ∩ B) = P(A) P(B) = 1/2 × p = 𝑝/2 Now, P(A ∪ B) = P(A) + P(B) – P(A ∩ B) Putting values 3/5 = 1/2 + p – 𝑝/2 3/2 – 1/2 = p – 𝑝/2 (6 − 5)/10 = 𝑝/2 1/10 = 𝑝/2 p = 2/10 p = 𝟏/𝟓