# Ex 13.2, 17 - Chapter 13 Class 12 Probability

Last updated at May 29, 2018 by Teachoo

Last updated at May 29, 2018 by Teachoo

Transcript

Ex 13.2, 17 The Probability of obtaining an even prime number on each die, when a pair of die is rolled is (A) 0 (B) 13 (C) 112 (D) 136 A pair of die is rolled S = Probability of obtaining an even prime number on each die = Probability of obtaining an even prime on first die × Probability of obtaining on even prime on second die, P(E ∩ E) = P(E) × P(E|E) Prime numbers are numbers which can only be divided by 1 and themselves. Example: 2, 3, 5, 7, 11, 13, …. E: Getting an even prime number on die Even prime number = 2 So, P(E) = Probability of obtaining even prime number on the first die = Probability of obtaining 2 on the first die = 16 P(E|E) = Probability of obtaining 2 on the second die, given that 2 was obtained on the first die. = 16 ∴ P(E ∩ E) = P(E) × P(E|E) = 16 × 16 = 𝟏𝟑𝟔 So, option (D) is correct

Chapter 13 Class 12 Probability

Serial order wise

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