Approximations (using Differentiation)
Last updated at December 16, 2024 by Teachoo
Transcript
Question 1 Using differentials, find the approximate value of each of the following up to 3 places of decimal. (x) ć(401)ć^(1/2)Let š¦=š„^( 1/2) where š„=400 & āš„=1 Now, šš¦/šš„=1/(2āš„) Using āš¦=šš¦/šš„ āš„ āš¦=šš¦/(2āš„) āš„ Putting Values āš¦=1/(2ā400) Ć(1) āš¦=1/(2ā400) Ć(1) āš¦=1/(2ā(20^2 )) āš¦=1/(2 Ć 20) āš¦=1/40 āš¦=0. 025 We know that āš¦=š(š„+āš„)āš(š„) So, āš¦= (š„+āš„)^( 1/2)ā(š„)^( 1/2) Putting Values 0. 025=(400+1)^( 1/(2 ))āć(400) ć^(1/2) 0. 025=(401)^( 1/2)ā(20)^( 2 Ć 1/2) 0. 025=(401)^( 1/2)ā20 0. 025+20=(401)^( 1/2) 20. 025=(401)^( 1/2) We know that āš¦=š(š„+āš„)āš(š„) So, āš¦= (š„+āš„)^( 1/2)ā(š„)^( 1/2) Putting Values 0. 025=(400+1)^( 1/(2 ))āć(400) ć^(1/2) 0. 025=(401)^( 1/2)ā(20)^( 2 Ć 1/2) 0. 025=(401)^( 1/2)ā20 0. 025+20=(401)^( 1/2) 20. 025=(401)^( 1/2)