Check sibling questions

 


Transcript

Ex 1.1, 4 Show that the relation R in R defined as R = {(a, b) : a ≤ b}, is reflexive and transitive but not symmetric. R = { (a, b) : a ≤ b } Here R is set of real numbers Hence, both a and b are real numbers Check reflexive We know that a = a ∴ a ≤ a ⇒ (a, a) ∈ R ∴ R is reflexive. Check symmetric To check whether symmetric or not, If (a, b) ∈ R, then (b, a) ∈ R i.e., if a ≤ b, then b ≤ a Since b ≤ a is not true for all values of a & b Hence, the given relation is not symmetric Check transitive If a ≤ b, & b ≤ c , then a ≤ c ∴ If (a, b) ∈ R & (b, c) ∈ R , then (a, c) ∈ R Hence, the given relation is transitive Hence, R = {(a, b) : a ≤ b}, is reflexive and transitive but not symmetric

  1. Chapter 1 Class 12 Relation and Functions
  2. Serial order wise

About the Author

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo