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Ex 11.2, 4 Find the equation of the line which passes through the point (1, 2, 3) and is parallel to the vector 3๐‘– ฬ‚ + 2๐‘— ฬ‚ โ€“ 2๐‘˜ ฬ‚ . Equation of a line passing through a point with position vector ๐‘Ž โƒ—, and parallel to a vector ๐‘ โƒ— is ๐’“ โƒ— = ๐’‚ โƒ— + ๐œ†๐’ƒ โƒ— Since line passes through (1, 2, 3) ๐’‚ โƒ— = 1๐’Š ฬ‚ + 2๐’‹ ฬ‚ + 3๐’Œ ฬ‚ Since line is parallel to 3๐‘– ฬ‚ + 2๐‘— ฬ‚ โˆ’ 2๐‘˜ ฬ‚ ๐’ƒ โƒ— = 3๐’Š ฬ‚ + 2๐’‹ ฬ‚ โˆ’ 2๐’Œ ฬ‚ Equation of line ๐‘Ÿ โƒ— = ๐‘Ž โƒ— + ๐œ†๐‘ โƒ— ๐’“ โƒ— = (๐’Š ฬ‚ + 2๐’‹ ฬ‚ + 3๐’Œ ฬ‚) + ๐œ† (3๐’Š ฬ‚ + 2๐’‹ ฬ‚ โˆ’ 2๐’Œ ฬ‚)

  1. Chapter 11 Class 12 Three Dimensional Geometry
  2. Serial order wise

About the Author

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo