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Misc 18 (Introduction) The value of ๐‘– ฬ‚.(๐‘— ฬ‚ ร— ๐‘˜ ฬ‚) + ๐‘— ฬ‚. (๐‘– ฬ‚ ร— ๐‘˜ ฬ‚) + ๐‘˜ ฬ‚.(๐‘– ฬ‚ ร— ๐‘— ฬ‚) (A) 0 (B) โˆ’1 (C) 1 (D) 3 ๐’Š ฬ‚ ร— ๐’‹ ฬ‚ = ๐‘˜ ฬ‚ ๐’‹ ฬ‚ ร— ๐’Œ ฬ‚ = ๐‘– ฬ‚ ๐’Œ ฬ‚ ร— ๐’Š ฬ‚ = ๐‘— ฬ‚ ๐’‹ ฬ‚ ร— ๐’Š ฬ‚ = โ€“๐‘˜ ฬ‚ ๐’Œ ฬ‚ ร— ๐’‹ ฬ‚ = โˆ’๐‘– ฬ‚ ๐’Š ฬ‚ ร— ๐’Œ ฬ‚ = โˆ’๐‘— ฬ‚ Misc 18 The value of ๐‘– ฬ‚.(๐‘— ฬ‚ ร— ๐‘˜ ฬ‚) + ๐‘— ฬ‚. (๐‘– ฬ‚ ร— ๐‘˜ ฬ‚) + ๐‘˜ ฬ‚.(๐‘– ฬ‚ ร— ๐‘— ฬ‚) (A) 0 (B) โˆ’1 (C) 1 (D) 3 Now, ๐‘– ฬ‚.(๐‘— ฬ‚ ร— ๐‘˜ ฬ‚) + ๐‘— ฬ‚. (๐‘– ฬ‚ ร— ๐‘˜ ฬ‚) + ๐‘˜ ฬ‚.(๐‘– ฬ‚ ร— ๐‘— ฬ‚) = ๐‘– ฬ‚.(๐’Š ฬ‚) + ๐‘— ฬ‚.(โˆ’๐’‹ ฬ‚) + ๐‘˜ ฬ‚ .(๐’Œ ฬ‚) = ๐‘– ฬ‚. ๐‘– ฬ‚ โˆ’ ๐‘— ฬ‚ . ๐‘— ฬ‚ + ๐‘˜ ฬ‚. ๐‘˜ ฬ‚ = 1 โ€“ 1 + 1 = 1 So, option C is correct ๐‘– ฬ‚. ๐‘– ฬ‚ = |๐‘– ฬ‚ ||๐‘– ฬ‚ | cos 0 = 1 ร— 1 ร— 1 = 1 Similarly, ๐‘— ฬ‚ . ๐‘— ฬ‚ = ๐‘˜ ฬ‚ . ๐‘˜ ฬ‚ = 1

  1. Chapter 10 Class 12 Vector Algebra
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About the Author

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo