Last updated at Dec. 16, 2024 by Teachoo
Misc 5 Find the value of x for which x(๐ ฬ + ๐ ฬ + ๐ ฬ) is a unit vector.Let ๐ โ = x(๐ ฬ + ๐ ฬ + ๐ ฬ) So, ๐ โ = ๐ฅ๐ ฬ + ๐ฅ๐ ฬ + ๐ฅ๐ ฬ Given, ๐ โ is a unit vector Magnitude of ๐ โ is 1. So, |๐ โ | = 1 Thus, Magnitude of ๐ โ = 1 โ(๐ฅ^2+๐ฅ2+๐ฅ2) = 1 โ3๐ฅ2 = 1 ยฑโ3 ๐ฅ = 1 ๐ = ยฑ๐/โ๐ Note We take ยฑ because x can have both positive and negative value
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo