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Misc 5 Find the value of x for which x(๐‘– ฬ‚ + ๐‘— ฬ‚ + ๐‘˜ ฬ‚) is a unit vector.Let ๐‘Ž โƒ— = x(๐‘– ฬ‚ + ๐‘— ฬ‚ + ๐‘˜ ฬ‚) So, ๐‘Ž โƒ— = ๐‘ฅ๐‘– ฬ‚ + ๐‘ฅ๐‘— ฬ‚ + ๐‘ฅ๐‘˜ ฬ‚ Given, ๐‘Ž โƒ— is a unit vector Magnitude of ๐‘Ž โƒ— is 1. So, |๐’‚ โƒ— | = 1 Thus, Magnitude of ๐’‚ โƒ— = 1 โˆš(๐‘ฅ^2+๐‘ฅ2+๐‘ฅ2) = 1 โˆš3๐‘ฅ2 = 1 ยฑโˆš3 ๐‘ฅ = 1 ๐’™ = ยฑ๐Ÿ/โˆš๐Ÿ‘ Note We take ยฑ because x can have both positive and negative value

  1. Chapter 10 Class 12 Vector Algebra
  2. Serial order wise

About the Author

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo