1. Chapter 5 Class 12 Continuity and Differentiability
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Question 22 - NCERT Exemplar - MCQs - Chapter 5 Class 12 Continuity and Differentiability

Last updated at Dec. 16, 2024 by Teachoo

If x = t 2 , y = t 3 , then (d 2 y)/(dx 2 ) is

(A) 3/2 

(B) 3/4t

(C) 3/2t 

(D) 3/4

This question is similar to Question 16 (Or 2nd) - CBSE Class 12 - Sample Paper for 2019 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards

Transcript

Question 22 If x = t2, y = t3, then (๐‘‘^2 ๐‘ฆ)/(๐‘‘๐‘ฅ^2 ) is (A) 3/2 (B) 3/4๐‘ก (C) 3/2๐‘ก (D) 3/4 ๐‘ฅ=๐‘ก^2 & ๐‘ฆ=๐‘ก^3 Finding ๐’…๐’š/๐’…๐’™ ๐’…๐’š/๐’…๐’™=(๐’…๐’š/๐’…๐’•)/(๐’…๐’™/๐’…๐’•) Finding ๐’…๐’š/๐’…๐’• ๐‘ฆ=๐‘ก^3 ๐‘‘๐‘ฆ/๐‘‘๐‘ก=(๐‘‘(๐‘ก^3))/๐‘‘๐‘ก ๐’…๐’š/๐’…๐’•=๐Ÿ‘๐’•^๐Ÿ Finding ๐’…๐’™/๐’…๐’• ๐‘ฅ =๐‘ก^2 ๐‘‘๐‘ฅ/๐‘‘๐‘ก=(๐‘‘(๐‘ก^2))/๐‘‘๐‘ก ๐’…๐’™/๐’…๐’•=๐Ÿ๐’• Now, ๐’…๐’š/๐’…๐’™=(๐’…๐’š/๐’…๐’•)/(๐’…๐’™/๐’…๐’•) =(3๐‘ก^2)/2๐‘ก =๐Ÿ‘๐’•/๐Ÿ Finding (๐’…^๐Ÿ ๐’š)/(๐’…๐’™^๐Ÿ ) (๐’…^๐Ÿ ๐’š)/(๐’…๐’™^๐Ÿ )=๐‘‘(3๐‘ก/2)/๐‘‘๐‘ฅ =๐‘‘(3๐‘ก/2)/๐‘‘๐‘กร—๐’…๐’•/๐’…๐’™ =3/2ร—๐‘‘๐‘ก/๐‘‘๐‘ฅ =3/2ร—๐Ÿ/(๐’…๐’™/๐’…๐’•) Putting ๐‘‘๐‘ฅ/๐‘‘๐‘ก=2๐‘ก =3/2ร—๐Ÿ/๐Ÿ๐’• =๐Ÿ‘/๐Ÿ’๐’• So, the correct answer is (B)
  1. Chapter 5 Class 12 Continuity and Differentiability
  2. Serial order wise

    3. NCERT Exemplar - MCQs

    Rolle's and Mean Value Theorem →
Rolle's and Mean Value Theorem →
Chapter 5 Class 12 Continuity and Differentiability
Serial order wise

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo