Ex 12.3, 2 (ii) - Divide (3y^8 - 4y^6 + 5y^4) รท y^4 - Polynomial by - Ex 12.3

part 2 - Ex 12.3, 2 (ii) - Ex 12.3 - Serial order wise - Chapter 12 Class 8 Factorisation

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Ex 12.3, 2 (Method 1) Divide the given polynomial by the given monomial. (ii) (3๐‘ฆ^8 โ€“ 4๐‘ฆ^6 + 5๐‘ฆ^4) รท ๐‘ฆ^43๐‘ฆ^8 โ€“ 4๐‘ฆ^6 + 5๐‘ฆ^4 = (3๐‘ฆ^4ร—๐‘ฆ^4 ) โˆ’ (4y^2ร—๐‘ฆ^4 )+(5ร—y^4) Taking ๐‘ฆ^4 common = ๐‘ฆ^4 (3๐‘ฆ^4 โˆ’ 4๐‘ฆ^2+5) Dividing (3๐‘ฆ^8 โˆ’ 4๐‘ฆ^6 + 5๐‘ฆ^4)/๐‘ฆ^4 = (๐‘ฆ^4 (3๐‘ฆ^4 โˆ’ ใ€–4๐‘ฆใ€—^4 + 5))/๐‘ฆ^4 = ๐Ÿ‘๐’š^๐Ÿ’ โˆ’ ๐Ÿ’๐’š^๐Ÿ + ๐Ÿ“ Ex 12.3, 2 (Method 2) Divide the given polynomial by the given monomial. (ii) (3๐‘ฆ^8 โ€“ 4๐‘ฆ^6 + 5๐‘ฆ^4) รท ๐‘ฆ^4 (3๐‘ฆ^8 โˆ’ 4๐‘ฆ^6 + 5๐‘ฆ^4)/๐‘ฆ^4 = (๐Ÿ‘๐’š^๐Ÿ–)/๐’š^๐Ÿ’ โˆ’ใ€–๐Ÿ’๐’šใ€—^๐Ÿ”/๐’š^๐Ÿ’ +(๐Ÿ“๐’š^๐Ÿ’)/๐’š^๐Ÿ’ = 3ร—๐‘ฆ^(8 โˆ’ 4)โˆ’ 4ร— ๐‘ฆ^(6 โˆ’ 4)+5ร—๐‘ฆ^(4 โˆ’ 4) = 3ร—๐‘ฆ^4โˆ’ 4ร— ๐‘ฆ^2+ใ€–5๐‘ฆใ€—^0 = ใ€–๐Ÿ‘๐’šใ€—^๐Ÿ’ โˆ’ ๐Ÿ’๐’š^๐Ÿ+๐Ÿ“ (๐ด๐‘  ๐‘Ž^๐‘š/๐‘Ž^๐‘› =๐‘Ž^(๐‘š โˆ’ n) ) (As ๐‘Ž^0=1)

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