Factorisation using identities
Last updated at July 14, 2026 by Teachoo
Transcript
Ex 12.2, 4 Factorise. (iv) š„^4 ā ć"(x ā z)" ć^4š„^4 ā ć"(x ā z)" ć^4 = ć(š„^2)ć^2 ā [(š„ ā z)^2 ]^2 Using š^š ā š^š = (a + b) (a ā b) Here š=š„^2 and b = (š„ ā z)^2 = [š„^2+(š„ ā z)^2 ] [š„^2 ā(š„ ā z)^2] Using š^š ā š^š = (a + b) (a ā b) Here š=š„ and b = (š„ ā z) = [š„^2+(š„ ā z)^2 ] [š„+(š„ ā z)] [š„ ā (š„ ā z)] = [š„^2+(š„ ā z)^2 ] [š„+ š„ ā z] [š„ āš„+š§] = [š„^2+(š„ ā z)^2 ] [2š„ā z] [š§] = [š^š+(š^š+š^š ā ššš)][ššā š] [š] = [š„^2+š„^2+š§^2 ā 2š„š§][2š„ā z] [š§] = [ć2š„ć^2+š§^2 ā 2š„š§][2š„ā z] [š§] = š³ (ššāš) (šš^š+š^š ā ššš) Using š^š ā š^š = š^2+š^2 ā 2ab Here š=š„ and b = š§