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  1. Chapter 14 Class 8 Factorisation
  2. Concept wise

Transcript

Ex 14.2, 2 Factorise. (iv) 16๐‘ฅ^5 โ€“ 144๐‘ฅ^3 16๐‘ฅ^5 โ€“ 144๐‘ฅ^3 = ใ€–16๐‘ฅใ€—^2 ๐‘ฅ^3โˆ’144๐‘ฅ^3 Taking ๐‘ฅ^3 common, = ๐‘ฅ^3 (16๐‘ฅ^2โˆ’144) = ๐‘ฅ^3 ((4๐‘ฅ)^2โˆ’(12)^2 ) Using ๐‘Ž^2โˆ’ ๐‘^2 = (a + b) (a โˆ’ b) Here a = 4x and b = 12 = ๐‘ฅ^3 (4๐‘ฅ+12) (4๐‘ฅโˆ’12) Both have 4 as common factor = ๐‘ฅ^3 ร— 4 (๐‘ฅ + 3) ร— 4 (๐‘ฅ โˆ’ 3) = ๐‘ฅ^3 ร— 4 ร— 4 (๐‘ฅ + 3) (๐‘ฅ โˆ’ 3) = 16๐’™^๐Ÿ‘ (๐’™ + 3) (๐’™ โˆ’ 3)

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.