Ex 12.2, 2 (iv) - Chapter 12 Class 8 Factorisation
Last updated at December 16, 2024 by Teachoo
Factorisation using identities
Factorisation using identities
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Ex 12.2, 2 Factorise. (iv) 16š„^5 ā 144š„^316š„^5 ā 144š„^3 = ć16š„ć^2 š„^3ā144š„^3 Taking š„^3 common, = š„^3 (16š„^2ā144) = š^š ((šš)^šā(šš)^š ) Using š^šā š^š = (a + b) (a ā b) Here a = 4x and b = 12 = š„^3 (4š„+12) (4š„ā12) = š„^3 (4š„+12) (4š„ā12) Both have 4 as common factor = š„^3 Ć 4 (š„ + 3) Ć 4 (š„ ā 3) = š„^3 Ć 4 Ć 4 (š„ + 3) (š„ ā 3) = 16š^š (š + 3) (š ā 3)
