Factorisation using identities
Last updated at December 16, 2024 by Teachoo
Transcript
Ex 12.2, 2 Factorise. (viii) 25š^2 ā 4š^2 + 28bc ā 49š^225š^2 ā 4š^2 + 28bc ā 49š^2 = 25š^2 ā (4š^2 ā 28bc +49š^2) = 25š^2 ā (4š^š + 49š^š + 28bc) = 25š^2 ā ((2b)2 + (7c)2 ā 2 Ć 2b Ć 7c) = 25š^2 ā "(2b ā " ć"7c)" ć^š = (5a)2 ā "(2b ā " ć"7c)" ć^š = (5a + (2b ā 7c)) (5a ā (2b ā 7c)) = (5a + 2b ā 7c) (5a ā 2b + 7c) Using š^š ā š^š = (š„ + y) (š„ ā y) Here x = 5a and y = 2b ā 7c