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  1. Chapter 14 Class 8 Factorisation
  2. Concept wise

Transcript

Ex 14.2, 2 Factorise. (viii) 25๐‘Ž^2 โ€“ 4๐‘^2 + 28bc โ€“ 49๐‘^2 25๐‘Ž^2 โ€“ 4๐‘^2 + 28bc โ€“ 49๐‘^2 Taking โˆ’ common = 25๐‘Ž^2 โˆ’ (4๐‘^2 โˆ’ 28bc +49๐‘^2) = 25๐‘Ž^2 โˆ’ (4๐‘^2 + 49๐‘^2 + 28bc) = 25๐‘Ž^2 โˆ’ ((2b)2 + (7c)2 โˆ’ 2 ร— 2b ร— 7c) Using (x โ€“ y)2 = x2 + y2 โ€“ 2xy Here x = 2b and y = 7c = 25๐‘Ž^2 โˆ’ "(2b โˆ’ " ใ€–"7c)" ใ€—^2 = (5a)2 โˆ’ "(2b โˆ’ " ใ€–"7c)" ใ€—^2 Using ๐‘ฅ^2 โˆ’ ๐‘ฆ^2 = (๐‘ฅ + y) (๐‘ฅ โˆ’ y) Here x = 5a and y = 2b โˆ’ 7c Using ๐‘ฅ^2 โˆ’ ๐‘ฆ^2 = (๐‘ฅ + y) (๐‘ฅ โˆ’ y) Here x = 5a and y = 2b โˆ’ 7c

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.