Ex 12.2, 2 (ii) - Chapter 12 Class 8 Factorisation

Last updated at August 13, 2026 by

Ex 12.2, 2 (ii) - Factorise 63^a2 - 112b^2 - Ex 12.2 - Ex 12.2

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Ex 12.2, 2 Factorise. (ii) 63𝑎^2 – 112𝑏^263𝑎^2 – 112𝑏^2 = (7 × 9)𝑎^2− (7 × 16)𝑏^2 Taking 7 common, = 7 (9𝑎^2−16b^2) = 7 ((𝟑𝒂^𝟐 )−(𝟒𝒃)^𝟐 ) Using 𝒙^𝟐−𝒚^𝟐=(𝑥+𝑦)(𝑥−𝑦) Here 𝑥=3𝑎 and 𝑦=4𝑏 = 7 (𝟑𝒂+𝟒𝒃) (𝟑𝒂−𝟒𝒃)

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