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Ex 14.1, 3 (ii) - Chapter 14 Class 8 Factorisation
Last updated at Dec. 26, 2018 by Teachoo
Transcript
Ex 14.1, 3 Factorise. (ii) 15 ๐ฅ๐ฆ โ 6x + 5๐ฆ โ 2 15 ๐ฅ๐ฆ โ 6x + 5๐ฆ โ 2 = (15๐ฅ๐ฆ โ 6๐ฅ) + (5๐ฆ โ 2) Both have 3 and x as common factor Since nothing is common, we take 1 common = 3๐ฅ (5y โ 2) + 1 ร (5y โ 2) Taking (5y โ 2) common = (5y โ 2) (3x + 1)
Ex 14.1
Ex 14.1, 1 (i)
Ex 14.1, 1 (ii)
Ex 14.1, 1 (iii)
Ex 14.1, 1 (iv)
Ex 14.1, 1 (v)
Ex 14.1, 1 (vi) Important
Ex 14.1, 1 (vii)
Ex 14.1, 1 (viii) Important
Ex 14.1, 2 (i)
Ex 14.1, 2 (ii)
Ex 14.1, 2 (iii)
Ex 14.1, 2 (iv)
Ex 14.1, 2 (v)
Ex 14.1, 2 (vi)
Ex 14.1, 2 (vii)
Ex 14.1, 2 (viii)
Ex 14.1, 2 (ix) Important
Ex 14.1, 2 (x) Important
Ex 14.1, 3 (i)
Ex 14.1, 3 (ii) Important You are here
Ex 14.1, 3 (iii) Important
Ex 14.1, 3 (iv) Important
Ex 14.1, 3 (v)
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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.