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Ex 14.1, 2 (v) - Factorise  20 l^2 m + 30 a l m - Chapter 14 Class 8

Ex 14.1, 2 (v) - Chapter 14 Class 8 Factorisation - Part 2
Ex 14.1, 2 (v) - Chapter 14 Class 8 Factorisation - Part 3

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Ex 14.1, 2 (Method 1) Factorise the following expressions. (v) 20 𝑙^2 m + 30 a l m 20 𝑙^2 m = 20 × 𝑙^2 × m = 2 × 2 × 5 × 𝑙^2 × m = 2 × 2 × 5 × l × l × m 30 alm = 30 × a × l × m = 2 × 3 × 5 × a × l × m So, 20 𝑙^2m = 2 × 2 × 5 × l × l × m 30 alm = 2 × 3 × 5 × a × l × m So, 2, 5, l and m are the common factors. Now, 20 𝑙^2m + 30 alm = (2 × 2 × 5 × l × l × m) + (2 × 3 × 5 × a × l × m) Taking 2 × 5 × l × m common = 2 × 5 × l × m (2 × l + 3 × a) = 10lm(2l + 3a) Ex 14.1, 2 (Method 2) Factorise the following expressions. (v) 20 𝑙^2 m + 30 a l m 20 𝑙^2 m + 30 a l m = (10 × 2) 𝑙^2 m + (10 × 3) alm Taking 10 common, = 10 × (2𝑙^2m + 3 alm) = 10 × ((2l × lm) + (3a × lm)) Taking lm common, = 10 × lm (2l + 3a) = 10lm (2l + 3a)

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.