
Ex 12.1
Last updated at Dec. 16, 2024 by Teachoo
Ex 12.1, 1 Find the common factors of the given terms. (vi) 〖16𝑥〗^3,−〖4𝑥〗^2, 32𝑥16𝒙^𝟑 = 16 × 𝑥^3 = 2 × 2 × 2 × 2 × 𝑥^3 = 2 × 2 × 2 × 2 × 𝒙 × 𝒙 × 𝒙 −4𝒙^𝟐 = −4 × 𝑥^2 = −1 × 4 × 𝑥^2 = −1 × 2 × 2 × 𝑥^2 = −1 × 2 × 2 × 𝒙 × 𝒙 32𝒙 = 32 × 𝑥 = 2 × 2 × 2 × 2 × 2 × 𝒙 So, 16𝒙^𝟑 = 2 × 2 × 2 × 2 × 𝑥 × 𝑥 × 𝑥 −4𝒙^𝟐 = −1 × 2 × 2 × 𝑥 × 𝑥 32𝒙 = 2 × 2 × 2 × 2 × 2 × 𝑥 So, Common factor = 2 × 2 × 𝑥 = 4 × 𝑥 = 4𝒙