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  1. Chapter 14 Class 8 Factorisation
  2. Serial order wise

Transcript

Ex 14.1, 2 (Method 1) Factorise the following expressions. (vi) 5 ๐‘ฅ^2 y โ€“ 15 ใ€–๐‘ฅ๐‘ฆใ€—^2 5 ๐‘ฅ^2 y = 5 ร— ๐‘ฅ ร— ๐‘ฅ ร— y 15 ๐‘ฅy^2 = 15 ร— ๐‘ฅ ร— ๐‘ฆ^2 = 3 ร— 5 ร— ๐‘ฅ ร— ๐‘ฆ^2 = 3 ร— 5 ร— ๐‘ฅ ร— ๐‘ฆ ร— ๐‘ฆ So, 5 ๐‘ฅ^2 y = 5 ร— ๐‘ฅ ร— ๐‘ฅ ร— y 15๐‘ฅ^2 y = 3 ร— 5 ร— ๐‘ฅ ร— ๐‘ฅ ร— y So, 5, ๐‘ฅ and y are the common factors. Now, 5 ๐‘ฅ^2y โ€“ 15 ใ€–๐‘ฅ๐‘ฆใ€—^2 = (5 ร— ๐‘ฅ ร— ๐‘ฅ ร— y) โˆ’ (3 ร— 5 ร— ๐‘ฅ ร— y ร— y) Taking 5 ร— ๐‘ฅ ร— y common = 5 ร— ๐‘ฅ ร— y (๐‘ฅ โˆ’ (3 ร— y)) = 5xy (x โˆ’ 3y) Ex 14.1, 2 (Method 2) Factorise the following expressions. (vi) 5 ๐‘ฅ^2 y โ€“ 15 ใ€–๐‘ฅ๐‘ฆใ€—^2 5 ๐‘ฅ^2y โ€“ 15 ใ€–๐‘ฅ๐‘ฆใ€—^2 = 5 ๐‘ฅ^2y โ€“ 5 ร— 3 ร— ใ€–๐‘ฅ๐‘ฆใ€—^2 Taking 5 ร— ๐‘ฅ ร— y common = 5 (๐‘ฅ^2y โˆ’ 3ใ€–๐‘ฅ๐‘ฆใ€—^2) = 5 ((๐‘ฅ๐‘ฆ ร— ๐‘ฅ) โˆ’ (๐‘ฅ๐‘ฆ ร— 3y)) Taking xy common, = 5๐’™y (๐’™ โˆ’ 3y)

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.