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Ex 14.1, 2 (vi) - Factorise  5 x^2 y - 15 xy^2  - Chapter 14 Class 8

Ex 14.1, 2 (vi) - Chapter 14 Class 8 Factorisation - Part 2
Ex 14.1, 2 (vi) - Chapter 14 Class 8 Factorisation - Part 3


Transcript

Ex 14.1, 2 (Method 1) Factorise the following expressions. (vi) 5 𝑥^2 y – 15 〖𝑥𝑦〗^2 5 𝑥^2 y = 5 × 𝑥 × 𝑥 × y 15 𝑥y^2 = 15 × 𝑥 × 𝑦^2 = 3 × 5 × 𝑥 × 𝑦^2 = 3 × 5 × 𝑥 × 𝑦 × 𝑦 So, 5 𝑥^2 y = 5 × 𝑥 × 𝑥 × y 15𝑥^2 y = 3 × 5 × 𝑥 × 𝑥 × y So, 5, 𝑥 and y are the common factors. Now, 5 𝑥^2y – 15 〖𝑥𝑦〗^2 = (5 × 𝑥 × 𝑥 × y) − (3 × 5 × 𝑥 × y × y) Taking 5 × 𝑥 × y common = 5 × 𝑥 × y (𝑥 − (3 × y)) = 5xy (x − 3y) Ex 14.1, 2 (Method 2) Factorise the following expressions. (vi) 5 𝑥^2 y – 15 〖𝑥𝑦〗^2 5 𝑥^2y – 15 〖𝑥𝑦〗^2 = 5 𝑥^2y – 5 × 3 × 〖𝑥𝑦〗^2 Taking 5 × 𝑥 × y common = 5 (𝑥^2y − 3〖𝑥𝑦〗^2) = 5 ((𝑥𝑦 × 𝑥) − (𝑥𝑦 × 3y)) Taking xy common, = 5𝒙y (𝒙 − 3y)

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.